[8-(3y+4)+16]+[4+(3y+4)]=

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Solution for [8-(3y+4)+16]+[4+(3y+4)]= equation: 


Simplifying
[8 + -1(3y + 4) + 16] + [4 + (3y + 4)] = 0

Reorder the terms:
[8 + -1(4 + 3y) + 16] + [4 + (3y + 4)] = 0
[8 + (4 * -1 + 3y * -1) + 16] + [4 + (3y + 4)] = 0
[8 + (-4 + -3y) + 16] + [4 + (3y + 4)] = 0

Reorder the terms:
[8 + -4 + 16 + -3y] + [4 + (3y + 4)] = 0

Combine like terms: 8 + -4 = 4
[4 + 16 + -3y] + [4 + (3y + 4)] = 0

Combine like terms: 4 + 16 = 20
[20 + -3y] + [4 + (3y + 4)] = 0

Remove brackets around [20 + -3y]
20 + -3y + [4 + (3y + 4)] = 0

Reorder the terms:
20 + -3y + [4 + (4 + 3y)] = 0

Remove parenthesis around (4 + 3y)
20 + -3y + [4 + 4 + 3y] = 0

Combine like terms: 4 + 4 = 8
20 + -3y + [8 + 3y] = 0

Remove brackets around [8 + 3y]
20 + -3y + 8 + 3y = 0

Reorder the terms:
20 + 8 + -3y + 3y = 0

Combine like terms: 20 + 8 = 28
28 + -3y + 3y = 0

Combine like terms: -3y + 3y = 0
28 + 0 = 0
28 = 0

Solving
28 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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